0=-16x^2+8x+87

Solution for 0=-16x^2+8x+87 equation:

0=-16x^2+8x+87

We move all terms to the left:

0-(-16x^2+8x+87)=0

We add all the numbers together, and all the variables

-(-16x^2+8x+87)=0

We get rid of parentheses

16x^2-8x-87=0

a = 16; b = -8; c = -87;
Δ = b2-4ac
Δ = -82-4·16·(-87)
Δ = 5632
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5632}=\sqrt{256*22}=\sqrt{256}*\sqrt{22}=16\sqrt{22}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-16\sqrt{22}}{2*16}=\frac{8-16\sqrt{22}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+16\sqrt{22}}{2*16}=\frac{8+16\sqrt{22}}{32}
$